Which of the following optioms correctly represents relationship between $t_{7/8}$ and $t_{1/2}$ where $t_{7/8}$ represent time required for concentration to become $\frac{1}{8} \,th$ of original for a reaction of order $'n'$
$t_{7/8} =(2n+ 1)\ t_{1/2}$
$t_{7/8} = t_{1/2}\, [2^{n-1} - 1]$
$t_{7/8} = t_{1/2}\, [2^{n-1} + 1]$
$t_{7/8} = t_{1/2}\, [2^{2n-2} + 1+2^{n-1}]$
For a certain reaction, the rate $=k[A]^2[B]$, when the initial concentration of $A$ is tripled keeping concentration of $B$ constant, the initial rate would
Assertion :The order of a reaction can have fractional value.
Reason : The order of a reaction cannot be written from balanced equation of a reaction.
For which type of reactions, order and molecularity have the same value ?
For the reaction $A + B \rightarrow$ products, it is observed that
$(i)\,\,$on doubling the initial concentration of $A$ only, the rate of reaction is also doubled and
$(ii)$ on doubling the initial concentration of both $A$ and $B,$ there is a change by a factor of $8$ in the rate of the reaction.
The rate of this reaction is given by
Consider the reaction :
$Cl_2(aq) + H_2S(aq) \to S(s) + 2H^+(aq) + 2Cl^-(aq)$
The rate equation for this reaction is rate $= k[Cl_2][H_2S]$ Which of these mechanisms is/are consistent with this rate equation ?
$A.\,C{l_2} + {H_2}S \to {H^ + } + C{l^ - } + C{l^ + } + H{S^- }$ (slow)
$C{l^ + } + H{S^ - } \to {H^ + } + C{l^ - } + {S}$ (fast)
$B.\, H_2S \Leftrightarrow H^+ + HS^-$ (fast equilibrium)
$Cl_2 + HS^-\to 2Cl^-+ H^+ + S$ (slow)